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PostPosted: Sun Jul 10, 2005 5:28 am 
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Moongewl wrote:
Anyway, looking at the problem logically, it could never happen, because how would you get ice from Terror Mountain to the Lost Desert without it melting on the way? Last time I checked, there were no refrigerated trucks in Neopia, and I haven't heard of any FedEx Faerie, either.


Maybe it started out at being 2 meters radius, but by the time it got to the lost desert, it melted down to 2 meters diameter! ;)


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PostPosted: Sun Jul 10, 2005 10:33 am 
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dood wrote:
hexagonal prism. Full explanation. (seing as people have differing answers)
Firstly, the length is 1.5 meters.
If you draw a line from each corner to the middle you'll cut the middle in 6. You've cut the middle of the hexagon into six equal angles. 360/6=60. All the lines you've drawn approach at the same angle to the edge as each other and so the other two angles are the same. 180-60 = 120. 120/2=60. and so all the angles of each triangle is 60 degrees. They're equilateral.
therefore, we use that Greek guys equation.
area of a triangle = root/ s x (s-a) (s-b) (s-c)
where a b and c = the sides of the triangle (all 1.5)
where s = semiperimeter (a+b+c)/2. which is 2.25
area of triangle = root/ 2.25 x 0.75 x 0.75 x 0.75
area of triangle = 0.974278579
there are six triangles and thus,
area of cross-section = 5.845671474 (six times area of triangle)
it's 0.8 meters deep.
5.845671474 x 0.8 = 4.676537.

I've changed bits of my explanation so some of you can understand easier. It's quite a hard equation though so you still may not understand.


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PostPosted: Sun Jul 10, 2005 4:51 pm 
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He's using Heron's Formula .

He cut the hexagon into six equilateral triangles.

Image

Then he used that formula, which is:

area of a triangle = sqrt[ s*(s-a)*(s-b)*(s-c) ]
s = (a+b+c)/2

where a, b, and c are sides of the triangle.

Since a, b, and c are all 1.5 meters, he got the area of each triangle by getting s in the bottom equation, then plugging everything into the top equation. (Area = 0.974278... m^2) He then multiplied that by 6 for the area of the whole hexagon, and then multiplied by 0.8 for the height of the pool, to get 4.676537 m^3.


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PostPosted: Mon Jul 11, 2005 6:14 am 
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Location: Antarctica or space...you get the idea already.
I still say the ball's mass is lower than the tub's volume.

Google for area of a hexagon, then multiply your area by the depth of the tub.

Then google for area of a sphere.


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PostPosted: Mon Jul 11, 2005 4:12 pm 
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AySz88 wrote:
He's using Heron's Formula .

He cut the hexagon into six equilateral triangles.

Image

Then he used that formula, which is:

area of a triangle = sqrt[ s*(s-a)*(s-b)*(s-c) ]
s = (a+b+c)/2

where a, b, and c are sides of the triangle.

Since a, b, and c are all 1.5 meters, he got the area of each triangle by getting s in the bottom equation, then plugging everything into the top equation. (Area = 0.974278... m^2) He then multiplied that by 6 for the area of the whole hexagon, and then multiplied by 0.8 for the height of the pool, to get 4.676537 m^3.

thanks ;) I guess teaching just en't my style...


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 Post subject: Wait a second...
PostPosted: Mon Jul 11, 2005 5:28 pm 
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Last time I checked, I didn't fill a bath tub up all the way. When you get in a bath, your volume is added to that of the water and if the bath was already filled all the way to the top, the water would overflow. So you don't really need enough water to fill the whole tub (except for the fact that it says "bath to be completely full") o_O Whatever.


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PostPosted: Mon Jul 11, 2005 6:44 pm 
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That's the first thing I thought.
"The amount of minutes until she gets in"


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