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 Post subject: Re: Homework Help Thread--SPLIT
PostPosted: Mon Oct 15, 2007 8:28 pm 
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Moongewl wrote:
Parts of speech are for individual words.

Try telling that to the people who wrote my grammar workbook. *kicks their bad grammar and hypocrisy*


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 Post subject: Re: Homework Help Thread--SPLIT
PostPosted: Sat Nov 10, 2007 4:40 am 
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Anoohilator wrote:
What is the overall capacitance of two capacitors in parallel, C1 and C2?

------------

guineadan wrote:
Whilst flicking through my homework planner, I see that I have maths due in on tuesday :P
I'm stuck on the last question (I thought it was going a bit too well xD). So, here it is ^^

Find the maximum and minimum points (if any) of the following graphs:
e) y= 3x^4 - 8x^3 + 6x^2 + 1

Therefore:

dy/dx = 12x^3 - 24x^2 + 12x , which simplifies to:
dy/dx = x^3 - 2x^2 + x

Is it even possible to factorise this to get values of x? o_O
I've tried making the -2x^2 + x part into brackets:
(-2x-1)(x-1), then adding the x to make it cubic:
x(-2x-1)(x-1) - but that doesn't work because there's a silly little 2 in front of that x^2 :p To factorise the quadratic bit, you need a 2 there though =S I know how to use the (d^2y)/(dx^2) thing - I just need help on this first bit :)

Suggestions, anyone?


You take 12x out as opposed to just twelve so you're left with 12x(x²-2x+1).


Yeah, so it'd be like:

12x(x-1)^2 = 0
x=0 or x=1

Then you can just carry on with the sign test/ second derivative test.


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 Post subject: Re: Homework Help Thread--SPLIT
PostPosted: Sat Dec 29, 2007 10:08 am 
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I've got this really annoying logarithm problem that I can't solve... help?

a + log a = 10
b + 10^b = 10

Find a + b.

Can anybody help?


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 Post subject: Re: Homework Help Thread--SPLIT
PostPosted: Sat Dec 29, 2007 10:09 pm 
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CWisgood wrote:
I've got this really annoying logarithm problem that I can't solve... help?

a + log a = 10
b + 10^b = 10

Find a + b.

Can anybody help?

a + log a = 10 = 10^b + b
b = log a => a + b = a + log a = 10
(or a = 10^b => 10^b + log 10 ^ b = 10^b + b = 10)

The difficult part is proving that b = log a (or equivalently stated as a = 10^b) is the
only relation between a and b that fulfills the first equation, but judging by the nature of the answer, you are not required to do so.


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 Post subject: Re: Homework Help Thread--SPLIT
PostPosted: Sat Mar 08, 2008 6:37 am 
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In psychology, I am supposed to find out about the psychodynamic explanation of aggression.
Can anyone please help out because I don't quite understand its concepts.


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 Post subject: Re: Homework Help Thread--SPLIT
PostPosted: Sun Apr 06, 2008 6:41 pm 
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Where can I find a really good website for texts of books one might read in school? It would be very handy for when I miss school and leave the book there, like on Friday, or when I need a quote for an essay but just can't find it. I have only been able to find online study guides, but not actual full book texts. Please help. I don't want to have to make this up on Monday as well as all the homework I'm gonna get that day anyway.


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 Post subject: Re: Homework Help Thread--SPLIT
PostPosted: Mon Apr 07, 2008 4:37 am 
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I know there are a few sites like gutenberg.org and ibiblio.org that are pretty good.

Just keep in mind that these sites link to/host publications that are in the public domain. I also think that some publications may have different versions (different translations and whatnot), so just remember to stay consistent with the version that is being used in class.


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 Post subject: Re: Homework Help Thread--SPLIT
PostPosted: Tue Apr 08, 2008 3:43 am 
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Tymaporer wrote:
Where can I find a really good website for texts of books one might read in school? It would be very handy for when I miss school and leave the book there, like on Friday, or when I need a quote for an essay but just can't find it. I have only been able to find online study guides, but not actual full book texts. Please help. I don't want to have to make this up on Monday as well as all the homework I'm gonna get that day anyway.

My professor showed us a site where you can find illegal scanned copies of various books, but I don't remember what it was and wouldn't feel comfortable sharing it anyway -- like I said, the copies are mostly illegal (it's run Napster-style). You could try the publishing company's website -- for newer texts, there's often a way to register and access content on-line.

I guess that's the advantage of grad school -- because the material is so recent, there aren't very many textbooks, so you can access most course materials on-line. Of course, I pay over $600/semester on books and downloaded articles, because the books you do have to buy are rather pricy.


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 Post subject: Re: Homework Help Thread--SPLIT
PostPosted: Wed Apr 09, 2008 2:59 am 
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Siniri wrote:
I guess that's the advantage of grad school -- because the material is so recent, there aren't very many textbooks, so you can access most course materials on-line. Of course, I pay over $600/semester on books and downloaded articles, because the books you do have to buy are rather pricy.


Man I wish my texts had only cost me 600 a semester. 2-3 books per class in my last year of Uni added up WAY too fast. Art supplies not included. And then the whole... "oh we can't buy back your texts because they're out of date already" BLAGH!


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 Post subject: Re: Homework Help Thread--SPLIT
PostPosted: Wed Apr 09, 2008 8:47 am 
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Try Law School. NOW THOSE texts are hella expensive.


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 Post subject: Re: Homework Help Thread--SPLIT
PostPosted: Wed Apr 09, 2008 6:44 pm 
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Kym-sensei wrote:
Try Law School. NOW THOSE texts are hella expensive.

You know the most commonly stolen books from university libraries fall into two categories? Law books and Theology books.


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 Post subject: Re: Homework Help Thread--SPLIT
PostPosted: Thu Apr 10, 2008 12:41 am 
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Psh, mine were $750 this semester. One of the ones that was $100 was opened a total of two times, for a combined total of about 15 minutes.

Waste of money, much?

I hate this school sometimes >.> And they estimated they'd be about $400.

I am not sure how hospitality management texts can cost so much o.O


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 Post subject: Re: Homework Help Thread--SPLIT
PostPosted: Thu Apr 10, 2008 3:37 am 
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I'm in business and public health school. I tend to buy all of my textbooks from amazon marketplace -- the "new" ones are usually about the same as the used ones from the bookstore, and I've had good experiences in terms of quality and speed (the marketplace is actually faster than amazon supersaver shipping). The business books are ridiculous; they run $140-160 retail. Fortunately, I only had to buy 3 texts this semester (+ several on-line course packets at $30-$100+ apiece).

I can imagine law books are even worse -- lawyers value their time very highly. At least after a few courses in public health, a lot of the required texts ended up being the same for multiple courses -- the first semester was over $800, though. But I know at least 2 of my textbooks had new editions published this year, so I'll have to rebuy those ones when I go back to public health classes in the fall. Hopefully there'll be some good deals on amazon marketplace!

Oh, and I know what you mean about hardly opening the text -- I've only used most of mine one or two times this semester!


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 Post subject: Re: Homework Help Thread--SPLIT
PostPosted: Tue Apr 22, 2008 12:50 am 
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Simple Math Question

What is -4^2? The BD Chat has been having a giant discussion about whether it is 16 or -16, so which is it?


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 Post subject: Re: Homework Help Thread--SPLIT
PostPosted: Tue Apr 22, 2008 1:21 am 
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Quote:
Since the product of two real negative numbers is positive, and the product of two real positive numbers is also positive, it follows that no square number is negative.

From Wikipedia.

It's 16. The reason people are getting -16 as a result is they're just putting -4^2 in a calculator. If you do (-4)^2, you'll get 16.

Let's break this down: To square a number is to multiply it by itself. Thus, -4^2 is the same as -4 x -4. The result is 16.


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