arogance1 wrote:
sirclucky wrote:
Erm, this lenny c is messed up. Think about it
The Mau Codestone's cost was equal to the Tai-Kai Codestone plus half the cost of the Main Codestone.
Unless the tai-kai codestone costs negative, which is impossible, the mau codestone costs more than half of the main codestone, so Mau > Main / 2.
You paid three times as much for the Mau Codestone as you did for the Main codestone.
From here we know that 3 * Mau = Main so
Mau = Main / 3
That means main / 3 > main / 2. This is only possible when 2 > 3 or Main <= 0. But its the show wizard. Can't buy stuff for under 1 np.
Mau = Tai-kai + (Main/2)
Tai-Kai = Eo - Main
Main = Mau/3
Eo = Tai-Kai + Main
The Mau Codestone's cost was equal to the Tai-Kai Codestone plus half the cost of the Main Codestone.
Mau = Tai-kai + (Main / 2)
The Tai-Kai Codestone's cost was the same as the Eo Codestone minus the cost of the Main Codestone.
Tai-Kai = Eo - Main
You paid three times as much for the Mau Codestone as you did for the Main codestone.
3*Mau = Main --> Mau = Main / 3
The Eo Codestone cost as much as the Tai-Kai and the Main Codestones put together.
Eo = Tai-Kai + Main
I rest my case
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