Lenny Conundrum 171

[sirclucky]

Erm, this lenny c is messed up. Think about it

The Mau Codestone's cost was equal to the Tai-Kai Codestone plus half the cost of the Main Codestone.

Unless the tai-kai codestone costs negative, which is impossible, the mau codestone costs more than half of the main codestone, so Mau > Main / 2.

You paid three times as much for the Mau Codestone as you did for the Main codestone.

From here we know that 3 * Mau = Main so
Mau = Main / 3

That means main / 3 > main / 2. This is only possible when 2 > 3 or Main <= 0. But its the show wizard. Can't buy stuff for under 1 np.

Mau = Tai-kai + (Main/2)
Tai-Kai = Eo - Main
Main = Mau/3
Eo = Tai-Kai + Main

The Mau Codestone's cost was equal to the Tai-Kai Codestone plus half the cost of the Main Codestone.

Mau = Tai-kai + (Main / 2)

The Tai-Kai Codestone's cost was the same as the Eo Codestone minus the cost of the Main Codestone.

Tai-Kai = Eo - Main

You paid three times as much for the Mau Codestone as you did for the Main codestone.

3*Mau = Main --> Mau = Main / 3

The Eo Codestone cost as much as the Tai-Kai and the Main Codestones put together.

Eo = Tai-Kai + Main

I rest my case

[pipsqueeek]

You paid three times as much for the Mau Codestone as you did for the Main codestone.

3*Mau = Main --> Mau = Main / 3

If you paid three times as much for the mau as the main, then it would be mau=3main.

[arogance1]

You paid three times as much for the Mau Codestone as you did for the Main codestone.

3*Mau = Main --> Mau = Main / 3

If you paid three times as much for the mau as the main, then it would be mau=3main.

Yes, Mau = 3Main, which is the same as Main = Mau/3

I wrote it the way I did so it was easier to work out each codestone