Fri Jul 08, 2005 6:23 am
compare to my answer, i've got enought ice to melt.
Does anyone gets the answer over 1hr???
Does anyone gets the answer over 1hr???
Fri Jul 08, 2005 7:49 am
I churned the figures through excel and there isn't enough ice. It doesn't matter how much mass the outside of the ball has compared to the inside if the total mass is less than the volume of the bathtub.
On a personal note, no princess waits over an hour for a bath. She would get some servants to use a coupla hair dryers. My calculations put the total melting of the ball (in its current state) at 700 minutes. And it still would be too little.
Don't tell me the ball's mass would affect the level of the bath as it melts in it. It would still take up the same area no matter what amount of ice is melted.
On a personal note, no princess waits over an hour for a bath. She would get some servants to use a coupla hair dryers. My calculations put the total melting of the ball (in its current state) at 700 minutes. And it still would be too little.
Don't tell me the ball's mass would affect the level of the bath as it melts in it. It would still take up the same area no matter what amount of ice is melted.
Fri Jul 08, 2005 8:44 am
What kind of idiotic aisha takes a bath in ice water anyway? 
Fri Jul 08, 2005 9:23 am
Kess wrote:What kind of idiotic aisha takes a bath in ice water anyway?
She does live in the desert and obviously it wouldn't be as cold anymore if it is melting. A nice cool bath when you live in the middle of a hot desert sounds fine to me.
Fri Jul 08, 2005 10:14 am
Spoilt Aisha. Booooo... I got some crappy answer which i doubt is correct. Submitted it anyways
Fri Jul 08, 2005 12:10 pm
Sometimes I wish I had majored in math or physics just so I would know shortcuts and easier ways of solving these problems. Would make LC a lot easier.
Fri Jul 08, 2005 12:34 pm
I can't remember how to figure out the volume of a hexagonal prism...Now that I'm done with math(for a year, anyway), I pushed all that out of my brain. Is it the one with n minus 2 times (something)?
Fri Jul 08, 2005 5:15 pm
Moongewl wrote:I can't remember how to figure out the volume of a hexagonal prism...Now that I'm done with math(for a year, anyway), I pushed all that out of my brain. Is it the one with n minus 2 times (something)?
I have also done the calculatations and come up with weird numbers.
Try finding the area of a hexagon by splitting it up into parts you can recognize (squares and triangles). Then you can find the volume without a problem.
Fri Jul 08, 2005 6:31 pm
I fiddled around with area and volume and millimeters and meters and square whatevers, then chose a random amount that came up on my calculator.
Anyway, looking at the problem logically, it could never happen, because how would you get ice from Terror Mountain to the Lost Desert without it melting on the way? Last time I checked, there were no refrigerated trucks in Neopia, and I haven't heard of any FedEx Faerie, either.
EDIT: I think there's enough ice in the sphere to fill the tub. The formula for volume of a sphere is 4/3 x pi x (radius x radius x radius), and if the radius is 1, then it's 4/3 of pi, in meters(square meters? cubed meters?), which is more than what I got for the volume within the bathtub. I could be wrong, of course--you can only expect a nut like me to be right every so often.
Anyway, looking at the problem logically, it could never happen, because how would you get ice from Terror Mountain to the Lost Desert without it melting on the way? Last time I checked, there were no refrigerated trucks in Neopia, and I haven't heard of any FedEx Faerie, either.
EDIT: I think there's enough ice in the sphere to fill the tub. The formula for volume of a sphere is 4/3 x pi x (radius x radius x radius), and if the radius is 1, then it's 4/3 of pi, in meters(square meters? cubed meters?), which is more than what I got for the volume within the bathtub. I could be wrong, of course--you can only expect a nut like me to be right every so often.
Sat Jul 09, 2005 2:28 pm
Moongewl wrote:EDIT: I think there's enough ice in the sphere to fill the tub. The formula for volume of a sphere is 4/3 x pi x (radius x radius x radius), and if the radius is 1, then it's 4/3 of pi, in meters(square meters? cubed meters?), which is more than what I got for the volume within the bathtub. I could be wrong, of course--you can only expect a nut like me to be right every so often.
This is what I did as well, so I guess I'm a nut with you
Sat Jul 09, 2005 2:46 pm
I've got A-level maths and I couldn't do it...
sphere = 4Pi r^2
..............--------
................. 3........_______
and the bath = 6 (/9x3x3x3)
This makes the bath WAY too big for the ice to fill it...
sphere = 4Pi r^2
..............--------
................. 3........_______
and the bath = 6 (/9x3x3x3)
This makes the bath WAY too big for the ice to fill it...
Sat Jul 09, 2005 4:18 pm
Yikes, I hate math.
And if people that are actually good at math can't figure it out...
Count me out.
And if people that are actually good at math can't figure it out...
Count me out.
Sat Jul 09, 2005 5:27 pm
My volume for the prism is (27 sqrt(3) )/10 m^3 which is about 4.676537.... m^3 .
And I got 4pi/3 m^3 for the sphere like everyone else, which is about 4.1887.... m^3 .
I still think they messed up the radius and wrote "diameter". I doubt they'd do something like this on purpose. Of course, I could be wrong.
Moongewl - they moved the ice the same way our ice pops keep in our inventories forever. :p
And I got 4pi/3 m^3 for the sphere like everyone else, which is about 4.1887.... m^3 .
I still think they messed up the radius and wrote "diameter". I doubt they'd do something like this on purpose. Of course, I could be wrong.
Moongewl - they moved the ice the same way our ice pops keep in our inventories forever. :p
Sat Jul 09, 2005 5:39 pm
hexagonal prism. Full explanation. (seing as people have differing answers)
Firstly, the length is 1.5 meters.
If you draw a line from each corner to the middle you'll cut the middle in 6. As 360 devided by 6 = 60, all of these six triangles you now have are equilateral.
therefore, we use that Greek guys equation
area of a triangle = root/ s x (s-a) (s-b) (s-c)
where s = semiperimeter (which here, is 2.25)
area of triangle = root/ 2.25 x 0.75 x 0.75 x 0.75
area of triangle = 0.974278579
there are six triangles and thus,
area of cross-section = 5.845671474
it's 0.8 meters deep.
5.845671474 x 0.8 = 4.676537.
Firstly, the length is 1.5 meters.
If you draw a line from each corner to the middle you'll cut the middle in 6. As 360 devided by 6 = 60, all of these six triangles you now have are equilateral.
therefore, we use that Greek guys equation
area of a triangle = root/ s x (s-a) (s-b) (s-c)
where s = semiperimeter (which here, is 2.25)
area of triangle = root/ 2.25 x 0.75 x 0.75 x 0.75
area of triangle = 0.974278579
there are six triangles and thus,
area of cross-section = 5.845671474
it's 0.8 meters deep.
5.845671474 x 0.8 = 4.676537.
o_O
Sun Jul 10, 2005 2:56 am
dood wrote:hexagonal prism. Full explanation. (seing as people have differing answers)
Firstly, the length is 1.5 meters.
If you draw a line from each corner to the middle you'll cut the middle in 6. As 360 devided by 6 = 60, all of these six triangles you now have are equilateral.
therefore, we use that Greek guys equation
area of a triangle = root/ s x (s-a) (s-b) (s-c)
where s = semiperimeter (which here, is 2.25)
area of triangle = root/ 2.25 x 0.75 x 0.75 x 0.75
area of triangle = 0.974278579
there are six triangles and thus,
area of cross-section = 5.845671474
it's 0.8 meters deep.
5.845671474 x 0.8 = 4.676537.
Can I have that in English please, I'm Greek and I dont understand.